-2z=4(z+2)-2z

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Solution for -2z=4(z+2)-2z equation: 



-2z=4(z+2)-2z

We move all terms to the left:

-2z-(4(z+2)-2z)=0



We calculate terms in parentheses: -(4(z+2)-2z), so:

4(z+2)-2z

We add all the numbers together, and all the variables

-2z+4(z+2)

We multiply parentheses

-2z+4z+8

We add all the numbers together, and all the variables

2z+8

Back to the equation:

-(2z+8)



We get rid of parentheses

-2z-2z-8=0

We add all the numbers together, and all the variables

-4z-8=0

We move all terms containing z to the left, all other terms to the right

-4z=8

z=8/-4

z=-2

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