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5-1/2x=12+3x
We move all terms to the left:
5-1/2x-(12+3x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1/2x-(3x+12)+5=0
We get rid of parentheses
-1/2x-3x-12+5=0
We multiply all the terms by the denominator
-3x*2x-12*2x+5*2x-1=0
Wy multiply elements
-6x^2-24x+10x-1=0
We add all the numbers together, and all the variables
-6x^2-14x-1=0
a = -6; b = -14; c = -1;
Δ = b2-4ac
Δ = -142-4·(-6)·(-1)
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{43}}{2*-6}=\frac{14-2\sqrt{43}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{43}}{2*-6}=\frac{14+2\sqrt{43}}{-12} $
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