5+In(x-3)=2

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Solution for 5+In(x-3)=2 equation: 


Simplifying
5 + In(x + -3) = 2

Reorder the terms:
5 + nI(-3 + x) = 2
5 + (-3 * nI + x * nI) = 2
5 + (-3nI + nxI) = 2

Solving
5 + -3nI + nxI = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -3nI + -5 + nxI = 2 + -5

Reorder the terms:
5 + -5 + -3nI + nxI = 2 + -5

Combine like terms: 5 + -5 = 0
0 + -3nI + nxI = 2 + -5
-3nI + nxI = 2 + -5

Combine like terms: 2 + -5 = -3
-3nI + nxI = -3

Reorder the terms:
3 + -3nI + nxI = -3 + 3

Combine like terms: -3 + 3 = 0
3 + -3nI + nxI = 0

The solution to this equation could not be determined.

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