(12r-53)/6=2(r-(3/4))-8

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Solution for (12r-53)/6=2(r-(3/4))-8 equation: 


r in (-oo:+oo)

(12*r-53)/6 = 2*(r-(3/4))-8 // - 2*(r-(3/4))-8

(12*r-53)/6-(2*(r-(3/4)))+8 = 0

(12*r-53)/6-2*(r-3/4)+8 = 0

(12*r-53)/6+(-2*6*(r-3/4))/6+(6*8)/6 = 0

12*r-2*6*(r-3/4)+6*8-53 = 0

48-44 = 0

4 = 0

4/6 = 0

4/6 = 0 // * 6

4 = 0

4 = 0

r belongs to the empty set

r belongs to the empty set

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