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5+5x=(5/6)(x-1)
We move all terms to the left:
5+5x-((5/6)(x-1))=0
Domain of the equation: 6)(x-1))!=0We add all the numbers together, and all the variables
x∈R
5x-((+5/6)(x-1))+5=0
We multiply parentheses ..
-((+5x^2+5/6*-1))+5x+5=0
We multiply all the terms by the denominator
-((+5x^2+5+5x*6*-1))+5*6*-1))=0
We calculate terms in parentheses: -((+5x^2+5+5x*6*-1)), so:We add all the numbers together, and all the variables
(+5x^2+5+5x*6*-1)
We get rid of parentheses
5x^2+5x*6*+5-1
We add all the numbers together, and all the variables
5x^2+5x*6*+4
Wy multiply elements
5x^2+30x^2+4
We add all the numbers together, and all the variables
35x^2+4
Back to the equation:
-(35x^2+4)
-(35x^2+4)=0
We get rid of parentheses
-35x^2-4=0
a = -35; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-35)·(-4)
Δ = -560
Delta is less than zero, so there is no solution for the equation
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