5+3(2y-3)=-2(6y-7)+6y

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Solution for 5+3(2y-3)=-2(6y-7)+6y equation: 



5+3(2y-3)=-2(6y-7)+6y

We move all terms to the left:

5+3(2y-3)-(-2(6y-7)+6y)=0

We multiply parentheses

6y-(-2(6y-7)+6y)-9+5=0



We calculate terms in parentheses: -(-2(6y-7)+6y), so:

-2(6y-7)+6y

We add all the numbers together, and all the variables

6y-2(6y-7)

We multiply parentheses

6y-12y+14

We add all the numbers together, and all the variables

-6y+14

Back to the equation:

-(-6y+14)



We add all the numbers together, and all the variables

6y-(-6y+14)-4=0

We get rid of parentheses

6y+6y-14-4=0

We add all the numbers together, and all the variables

12y-18=0

We move all terms containing y to the left, all other terms to the right

12y=18

y=18/12

y=1+1/2

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