If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+8x=40
We move all terms to the left:
4x^2+8x-(40)=0
a = 4; b = 8; c = -40;
Δ = b2-4ac
Δ = 82-4·4·(-40)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{11}}{2*4}=\frac{-8-8\sqrt{11}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{11}}{2*4}=\frac{-8+8\sqrt{11}}{8} $
| 66=⁴/6x | | -7+5d=-3+3d | | Y^3=y^2 | | h+5=9h+45 | | 4g=-10+9g | | 54-3a=-9a | | 4z=-5z+99 | | 1/2n+1/2n=-4 | | 9/4x=29 | | 7b=77-4b | | 10u-14=4+8u | | 14=12-5t+3t | | 14=12–5t+3t | | 7(x-2)+19+5(2x+1)=44 | | 19-n=29 | | 8(y-9)-8=-56 | | -2w=-3w-11 | | x(-4)(5)=15 | | 60+3u=8u | | 7(2x)−3=19x−11 | | 4(p-12)+10p=-48 | | 4(p–12)+10p=-48 | | 3+7m=71 | | -9(w-6)=-4w+9 | | 36=3c-6(c-8) | | -1/x+4=-3/x-5 | | 3y11=16 | | -9(8+s)-8=-8 | | 100+(-7+11x)=180 | | -9(8+s)–8=-8 | | 5x+40=8(x+2) | | 3(x-5)=7x-15 |