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5+2x=3-2(2x+1)
We move all terms to the left:
5+2x-(3-2(2x+1))=0
We calculate terms in parentheses: -(3-2(2x+1)), so:We get rid of parentheses
3-2(2x+1)
determiningTheFunctionDomain -2(2x+1)+3
We multiply parentheses
-4x-2+3
We add all the numbers together, and all the variables
-4x+1
Back to the equation:
-(-4x+1)
2x+4x-1+5=0
We add all the numbers together, and all the variables
6x+4=0
We move all terms containing x to the left, all other terms to the right
6x=-4
x=-4/6
x=-2/3
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