2(3a+11)=(4a+38)

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Solution for 2(3a+11)=(4a+38) equation: 



2(3a+11)=(4a+38)

We move all terms to the left:

2(3a+11)-((4a+38))=0

We multiply parentheses

6a-((4a+38))+22=0



We calculate terms in parentheses: -((4a+38)), so:

(4a+38)

We get rid of parentheses

4a+38

Back to the equation:

-(4a+38)



We get rid of parentheses

6a-4a-38+22=0

We add all the numbers together, and all the variables

2a-16=0

We move all terms containing a to the left, all other terms to the right

2a=16

a=16/2

a=8

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