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5+2p-p=9+3(p+2)
We move all terms to the left:
5+2p-p-(9+3(p+2))=0
We add all the numbers together, and all the variables
p-(9+3(p+2))+5=0
We calculate terms in parentheses: -(9+3(p+2)), so:We get rid of parentheses
9+3(p+2)
determiningTheFunctionDomain 3(p+2)+9
We multiply parentheses
3p+6+9
We add all the numbers together, and all the variables
3p+15
Back to the equation:
-(3p+15)
p-3p-15+5=0
We add all the numbers together, and all the variables
-2p-10=0
We move all terms containing p to the left, all other terms to the right
-2p=10
p=10/-2
p=-5
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