(4+x)+x+x=199

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Solution for (4+x)+x+x=199 equation: 



(4+x)+x+x=199

We move all terms to the left:

(4+x)+x+x-(199)=0

We add all the numbers together, and all the variables

(x+4)+x+x-199=0

We add all the numbers together, and all the variables

2x+(x+4)-199=0

We get rid of parentheses

2x+x+4-199=0

We add all the numbers together, and all the variables

3x-195=0

We move all terms containing x to the left, all other terms to the right

3x=195

x=195/3

x=65

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