5+2/3x=-x=20

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Solution for 5+2/3x=-x=20 equation:



5+2/3x=-x=20
We move all terms to the left:
5+2/3x-(-x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
2/3x-(-1x)+5=0
We get rid of parentheses
2/3x+1x+5=0
We multiply all the terms by the denominator
1x*3x+5*3x+2=0
Wy multiply elements
3x^2+15x+2=0
a = 3; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·3·2
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{201}}{2*3}=\frac{-15-\sqrt{201}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{201}}{2*3}=\frac{-15+\sqrt{201}}{6} $

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