4(9x-5)=10(3x-17)-30

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Solution for 4(9x-5)=10(3x-17)-30 equation: 



4(9x-5)=10(3x-17)-30

We move all terms to the left:

4(9x-5)-(10(3x-17)-30)=0

We multiply parentheses

36x-(10(3x-17)-30)-20=0



We calculate terms in parentheses: -(10(3x-17)-30), so:

10(3x-17)-30

We multiply parentheses

30x-170-30

We add all the numbers together, and all the variables

30x-200

Back to the equation:

-(30x-200)



We get rid of parentheses

36x-30x+200-20=0

We add all the numbers together, and all the variables

6x+180=0

We move all terms containing x to the left, all other terms to the right

6x=-180

x=-180/6

x=-30

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