4(s-9)=6(s-3)+2

Solution for 4(s-9)=6(s-3)+2 equation:

4(s-9)=6(s-3)+2

We move all terms to the left:

4(s-9)-(6(s-3)+2)=0

We multiply parentheses

4s-(6(s-3)+2)-36=0


We calculate terms in parentheses: -(6(s-3)+2), so:

6(s-3)+2

We multiply parentheses

6s-18+2

We add all the numbers together, and all the variables

6s-16

Back to the equation:

-(6s-16)


We get rid of parentheses

4s-6s+16-36=0

We add all the numbers together, and all the variables

-2s-20=0

We move all terms containing s to the left, all other terms to the right

-2s=20

s=20/-2

s=-10