5+2(s+3)+(4s-5)=148

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Solution for 5+2(s+3)+(4s-5)=148 equation: 



5+2(s+3)+(4s-5)=148

We move all terms to the left:

5+2(s+3)+(4s-5)-(148)=0

We add all the numbers together, and all the variables

2(s+3)+(4s-5)-143=0

We multiply parentheses

2s+(4s-5)+6-143=0

We get rid of parentheses

2s+4s-5+6-143=0

We add all the numbers together, and all the variables

6s-142=0

We move all terms containing s to the left, all other terms to the right

6s=142

s=142/6

s=23+2/3

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