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4(2x+5)=4x+34+2(2x+3)
We move all terms to the left:
4(2x+5)-(4x+34+2(2x+3))=0
We multiply parentheses
8x-(4x+34+2(2x+3))+20=0
We calculate terms in parentheses: -(4x+34+2(2x+3)), so:We get rid of parentheses
4x+34+2(2x+3)
determiningTheFunctionDomain 4x+2(2x+3)+34
We multiply parentheses
4x+4x+6+34
We add all the numbers together, and all the variables
8x+40
Back to the equation:
-(8x+40)
8x-8x-40+20=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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