5+2(k+4)=(k-3)+10

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Solution for 5+2(k+4)=(k-3)+10 equation: 



5+2(k+4)=(k-3)+10

We move all terms to the left:

5+2(k+4)-((k-3)+10)=0

We multiply parentheses

2k-((k-3)+10)+8+5=0



We calculate terms in parentheses: -((k-3)+10), so:

(k-3)+10

We get rid of parentheses

k-3+10

We add all the numbers together, and all the variables

k+7

Back to the equation:

-(k+7)



We add all the numbers together, and all the variables

2k-(k+7)+13=0

We get rid of parentheses

2k-k-7+13=0

We add all the numbers together, and all the variables

k+6=0

We move all terms containing k to the left, all other terms to the right

k=-6

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