1/3(x+5)=1/2(2x-1)

Solution for 1/3(x+5)=1/2(2x-1) equation:

1/3(x+5)=1/2(2x-1)

We move all terms to the left:

1/3(x+5)-(1/2(2x-1))=0


Domain of the equation: 3(x+5)!=0

x∈R



Domain of the equation: 2(2x-1))!=0

x∈R


We calculate fractions


(2x2/(3(x+5)*2(2x-1)))+(-3xx/(3(x+5)*2(2x-1)))=0


We calculate terms in parentheses: +(2x2/(3(x+5)*2(2x-1))), so:

2x2/(3(x+5)*2(2x-1))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)



We calculate terms in parentheses: +(-3xx/(3(x+5)*2(2x-1))), so:

-3xx/(3(x+5)*2(2x-1))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2x^2-3xx=0