7(c-3)+4=3+c-20

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Solution for 7(c-3)+4=3+c-20 equation: 



7(c-3)+4=3+c-20

We move all terms to the left:

7(c-3)+4-(3+c-20)=0

We add all the numbers together, and all the variables

7(c-3)-(c-17)+4=0

We multiply parentheses

7c-(c-17)-21+4=0

We get rid of parentheses

7c-c+17-21+4=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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