5+2(4y-4)=-3(5y-3)+7y

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Solution for 5+2(4y-4)=-3(5y-3)+7y equation: 



5+2(4y-4)=-3(5y-3)+7y

We move all terms to the left:

5+2(4y-4)-(-3(5y-3)+7y)=0

We multiply parentheses

8y-(-3(5y-3)+7y)-8+5=0



We calculate terms in parentheses: -(-3(5y-3)+7y), so:

-3(5y-3)+7y

We add all the numbers together, and all the variables

7y-3(5y-3)

We multiply parentheses

7y-15y+9

We add all the numbers together, and all the variables

-8y+9

Back to the equation:

-(-8y+9)



We add all the numbers together, and all the variables

8y-(-8y+9)-3=0

We get rid of parentheses

8y+8y-9-3=0

We add all the numbers together, and all the variables

16y-12=0

We move all terms containing y to the left, all other terms to the right

16y=12

y=12/16

y=3/4

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