5(z+3)+2(z-4)=3(z-3)

Solution for 5(z+3)+2(z-4)=3(z-3) equation:

5(z+3)+2(z-4)=3(z-3)

We move all terms to the left:

5(z+3)+2(z-4)-(3(z-3))=0

We multiply parentheses

5z+2z-(3(z-3))+15-8=0


We calculate terms in parentheses: -(3(z-3)), so:

3(z-3)

We multiply parentheses

3z-9

Back to the equation:

-(3z-9)


We add all the numbers together, and all the variables

7z-(3z-9)+7=0

We get rid of parentheses

7z-3z+9+7=0

We add all the numbers together, and all the variables

4z+16=0

We move all terms containing z to the left, all other terms to the right

4z=-16

z=-16/4

z=-4