5(z+2)+3z=-3-(2z+7)

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Solution for 5(z+2)+3z=-3-(2z+7) equation: 



5(z+2)+3z=-3-(2z+7)

We move all terms to the left:

5(z+2)+3z-(-3-(2z+7))=0

We add all the numbers together, and all the variables

3z+5(z+2)-(-3-(2z+7))=0

We multiply parentheses

3z+5z-(-3-(2z+7))+10=0



We calculate terms in parentheses: -(-3-(2z+7)), so:

-3-(2z+7)

determiningTheFunctionDomain
-(2z+7)-3

We get rid of parentheses

-2z-7-3

We add all the numbers together, and all the variables

-2z-10

Back to the equation:

-(-2z-10)



We add all the numbers together, and all the variables

8z-(-2z-10)+10=0

We get rid of parentheses

8z+2z+10+10=0

We add all the numbers together, and all the variables

10z+20=0

We move all terms containing z to the left, all other terms to the right

10z=-20

z=-20/10

z=-2

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