5(2z+2)+3z=-3-(z+7)

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Solution for 5(2z+2)+3z=-3-(z+7) equation: 



5(2z+2)+3z=-3-(z+7)

We move all terms to the left:

5(2z+2)+3z-(-3-(z+7))=0

We add all the numbers together, and all the variables

3z+5(2z+2)-(-3-(z+7))=0

We multiply parentheses

3z+10z-(-3-(z+7))+10=0



We calculate terms in parentheses: -(-3-(z+7)), so:

-3-(z+7)

determiningTheFunctionDomain
-(z+7)-3

We get rid of parentheses

-z-7-3

We add all the numbers together, and all the variables

-1z-10

Back to the equation:

-(-1z-10)



We add all the numbers together, and all the variables

13z-(-1z-10)+10=0

We get rid of parentheses

13z+1z+10+10=0

We add all the numbers together, and all the variables

14z+20=0

We move all terms containing z to the left, all other terms to the right

14z=-20

z=-20/14

z=-1+3/7

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