5(y-2)2-2=2(y+1)-5

Solution for 5(y-2)2-2=2(y+1)-5 equation:

5(y-2)2-2=2(y+1)-5

We move all terms to the left:

5(y-2)2-2-(2(y+1)-5)=0

We multiply parentheses

10y-(2(y+1)-5)-20-2=0


We calculate terms in parentheses: -(2(y+1)-5), so:

2(y+1)-5

We multiply parentheses

2y+2-5

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)


We add all the numbers together, and all the variables

10y-(2y-3)-22=0

We get rid of parentheses

10y-2y+3-22=0

We add all the numbers together, and all the variables

8y-19=0

We move all terms containing y to the left, all other terms to the right

8y=19

y=19/8

y=2+3/8