3(2x-1)+7=6x-3-2(2x-4)

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Solution for 3(2x-1)+7=6x-3-2(2x-4) equation: 



3(2x-1)+7=6x-3-2(2x-4)

We move all terms to the left:

3(2x-1)+7-(6x-3-2(2x-4))=0

We multiply parentheses

6x-(6x-3-2(2x-4))-3+7=0



We calculate terms in parentheses: -(6x-3-2(2x-4)), so:

6x-3-2(2x-4)

determiningTheFunctionDomain
6x-2(2x-4)-3

We multiply parentheses

6x-4x+8-3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

6x-(2x+5)+4=0

We get rid of parentheses

6x-2x-5+4=0

We add all the numbers together, and all the variables

4x-1=0

We move all terms containing x to the left, all other terms to the right

4x=1

x=1/4

x=1/4

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