5(y+3)=9y-5

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Solution for 5(y+3)=9y-5 equation: 



5(y+3)=9y-5

We move all terms to the left:

5(y+3)-(9y-5)=0

We multiply parentheses

5y-(9y-5)+15=0

We get rid of parentheses

5y-9y+5+15=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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