5(y+3)=12y-4

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Solution for 5(y+3)=12y-4 equation: 



5(y+3)=12y-4

We move all terms to the left:

5(y+3)-(12y-4)=0

We multiply parentheses

5y-(12y-4)+15=0

We get rid of parentheses

5y-12y+4+15=0

We add all the numbers together, and all the variables

-7y+19=0

We move all terms containing y to the left, all other terms to the right

-7y=-19

y=-19/-7

y=2+5/7

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