20=4(3+u)

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Solution for 20=4(3+u) equation: 



20=4(3+u)

We move all terms to the left:

20-(4(3+u))=0

We add all the numbers together, and all the variables

-(4(u+3))+20=0



We calculate terms in parentheses: -(4(u+3)), so:

4(u+3)

We multiply parentheses

4u+12

Back to the equation:

-(4u+12)



We get rid of parentheses

-4u-12+20=0

We add all the numbers together, and all the variables

-4u+8=0

We move all terms containing u to the left, all other terms to the right

-4u=-8

u=-8/-4

u=+2

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