5(y+2)=6(y-5)

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Solution for 5(y+2)=6(y-5) equation: 



5(y+2)=6(y-5)

We move all terms to the left:

5(y+2)-(6(y-5))=0

We multiply parentheses

5y-(6(y-5))+10=0



We calculate terms in parentheses: -(6(y-5)), so:

6(y-5)

We multiply parentheses

6y-30

Back to the equation:

-(6y-30)



We get rid of parentheses

5y-6y+30+10=0

We add all the numbers together, and all the variables

-1y+40=0

We move all terms containing y to the left, all other terms to the right

-y=-40

y=-40/-1

y=+40

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