6(x+1)-2=2(x+2)+4x

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Solution for 6(x+1)-2=2(x+2)+4x equation: 



6(x+1)-2=2(x+2)+4x

We move all terms to the left:

6(x+1)-2-(2(x+2)+4x)=0

We multiply parentheses

6x-(2(x+2)+4x)+6-2=0



We calculate terms in parentheses: -(2(x+2)+4x), so:

2(x+2)+4x

We add all the numbers together, and all the variables

4x+2(x+2)

We multiply parentheses

4x+2x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

6x-(6x+4)+4=0

We get rid of parentheses

6x-6x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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