5(y+2)-(3y+1)=3

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Solution for 5(y+2)-(3y+1)=3 equation: 



5(y+2)-(3y+1)=3

We move all terms to the left:

5(y+2)-(3y+1)-(3)=0

We multiply parentheses

5y-(3y+1)+10-3=0

We get rid of parentheses

5y-3y-1+10-3=0

We add all the numbers together, and all the variables

2y+6=0

We move all terms containing y to the left, all other terms to the right

2y=-6

y=-6/2

y=-3

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