12y+6=6(2y+1)+

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Solution for 12y+6=6(2y+1)+ equation: 



12y+6=6(2y+1)+

We move all terms to the left:

12y+6-(6(2y+1)+)=0



We calculate terms in parentheses: -(6(2y+1)+), so:

6(2y+1)+

We add all the numbers together, and all the variables

6(2y+1)

We multiply parentheses

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

12y-12y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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