5(y+1)=-3(2y-5)+5y

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Solution for 5(y+1)=-3(2y-5)+5y equation: 



5(y+1)=-3(2y-5)+5y

We move all terms to the left:

5(y+1)-(-3(2y-5)+5y)=0

We multiply parentheses

5y-(-3(2y-5)+5y)+5=0



We calculate terms in parentheses: -(-3(2y-5)+5y), so:

-3(2y-5)+5y

We add all the numbers together, and all the variables

5y-3(2y-5)

We multiply parentheses

5y-6y+15

We add all the numbers together, and all the variables

-1y+15

Back to the equation:

-(-1y+15)



We get rid of parentheses

5y+1y-15+5=0

We add all the numbers together, and all the variables

6y-10=0

We move all terms containing y to the left, all other terms to the right

6y=10

y=10/6

y=1+2/3

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