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(-4x-6)(-5x-6)=0
We multiply parentheses ..
(+20x^2+24x+30x+36)=0
We get rid of parentheses
20x^2+24x+30x+36=0
We add all the numbers together, and all the variables
20x^2+54x+36=0
a = 20; b = 54; c = +36;
Δ = b2-4ac
Δ = 542-4·20·36
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6}{2*20}=\frac{-60}{40} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6}{2*20}=\frac{-48}{40} =-1+1/5 $
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