5(y+1)=(9y-7)

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Solution for 5(y+1)=(9y-7) equation: 



5(y+1)=(9y-7)

We move all terms to the left:

5(y+1)-((9y-7))=0

We multiply parentheses

5y-((9y-7))+5=0



We calculate terms in parentheses: -((9y-7)), so:

(9y-7)

We get rid of parentheses

9y-7

Back to the equation:

-(9y-7)



We get rid of parentheses

5y-9y+7+5=0

We add all the numbers together, and all the variables

-4y+12=0

We move all terms containing y to the left, all other terms to the right

-4y=-12

y=-12/-4

y=+3

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