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(2x+6)(4x-10)=0
We multiply parentheses ..
(+8x^2-20x+24x-60)=0
We get rid of parentheses
8x^2-20x+24x-60=0
We add all the numbers together, and all the variables
8x^2+4x-60=0
a = 8; b = 4; c = -60;
Δ = b2-4ac
Δ = 42-4·8·(-60)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44}{2*8}=\frac{-48}{16} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44}{2*8}=\frac{40}{16} =2+1/2 $
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