5(y+1)+7=4y+8

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Solution for 5(y+1)+7=4y+8 equation: 



5(y+1)+7=4y+8

We move all terms to the left:

5(y+1)+7-(4y+8)=0

We multiply parentheses

5y-(4y+8)+5+7=0

We get rid of parentheses

5y-4y-8+5+7=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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