5(x2+x2)+3=6(x2+x2+1)

Solution for 5(x2+x2)+3=6(x2+x2+1) equation:

5(x2+x2)+3=6(x2+x2+1)

We move all terms to the left:

5(x2+x2)+3-(6(x2+x2+1))=0

We add all the numbers together, and all the variables

5(+2x^2)-(6(+2x^2+1))+3=0

We multiply parentheses

10x^2-(6(+2x^2+1))+3=0


We calculate terms in parentheses: -(6(+2x^2+1)), so:

6(+2x^2+1)

We multiply parentheses

12x^2+6

Back to the equation:

-(12x^2+6)


We get rid of parentheses

10x^2-12x^2-6+3=0

We add all the numbers together, and all the variables

-2x^2-3=0

a = -2; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-2)·(-3)
Δ = -24
Delta is less than zero, so there is no solution for the equation