2(1+s)=3(2s-1)-23

Solution for 2(1+s)=3(2s-1)-23 equation:

2(1+s)=3(2s-1)-23

We move all terms to the left:

2(1+s)-(3(2s-1)-23)=0

We add all the numbers together, and all the variables

2(s+1)-(3(2s-1)-23)=0

We multiply parentheses

2s-(3(2s-1)-23)+2=0


We calculate terms in parentheses: -(3(2s-1)-23), so:

3(2s-1)-23

We multiply parentheses

6s-3-23

We add all the numbers together, and all the variables

6s-26

Back to the equation:

-(6s-26)


We get rid of parentheses

2s-6s+26+2=0

We add all the numbers together, and all the variables

-4s+28=0

We move all terms containing s to the left, all other terms to the right

-4s=-28

s=-28/-4

s=+7