5(x-6)+33=10+4x

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Solution for 5(x-6)+33=10+4x equation: 



5(x-6)+33=10+4x

We move all terms to the left:

5(x-6)+33-(10+4x)=0

We add all the numbers together, and all the variables

5(x-6)-(4x+10)+33=0

We multiply parentheses

5x-(4x+10)-30+33=0

We get rid of parentheses

5x-4x-10-30+33=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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