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4(x+3)=3(x-3)
We move all terms to the left:
4(x+3)-(3(x-3))=0
We multiply parentheses
4x-(3(x-3))+12=0
We calculate terms in parentheses: -(3(x-3)), so:We get rid of parentheses
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
4x-3x+9+12=0
We add all the numbers together, and all the variables
x+21=0
We move all terms containing x to the left, all other terms to the right
x=-21
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