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5(x-6)+3/2=1
We move all terms to the left:
5(x-6)+3/2-(1)=0
determiningTheFunctionDomain 5(x-6)-1+3/2=0
We multiply parentheses
5x-30-1+3/2=0
We multiply all the terms by the denominator
5x*2+3-30*2-1*2=0
We add all the numbers together, and all the variables
5x*2-59=0
Wy multiply elements
10x-59=0
We move all terms containing x to the left, all other terms to the right
10x=59
x=59/10
x=5+9/10
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