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2+5(v+2)=5(v+4)-8
We move all terms to the left:
2+5(v+2)-(5(v+4)-8)=0
We multiply parentheses
5v-(5(v+4)-8)+10+2=0
We calculate terms in parentheses: -(5(v+4)-8), so:We add all the numbers together, and all the variables
5(v+4)-8
We multiply parentheses
5v+20-8
We add all the numbers together, and all the variables
5v+12
Back to the equation:
-(5v+12)
5v-(5v+12)+12=0
We get rid of parentheses
5v-5v-12+12=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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