-3(2x+1)=2x(3x-4)

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Solution for -3(2x+1)=2x(3x-4) equation: 



-3(2x+1)=2x(3x-4)

We move all terms to the left:

-3(2x+1)-(2x(3x-4))=0

We multiply parentheses

-6x-(2x(3x-4))-3=0



We calculate terms in parentheses: -(2x(3x-4)), so:

2x(3x-4)

We multiply parentheses

6x^2-8x

Back to the equation:

-(6x^2-8x)



We get rid of parentheses

-6x^2-6x+8x-3=0

We add all the numbers together, and all the variables

-6x^2+2x-3=0

a = -6; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·(-6)·(-3)
Δ = -68
Delta is less than zero, so there is no solution for the equation

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