5(x-4)x+5y(y+2)+21=0

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Solution for 5(x-4)x+5y(y+2)+21=0 equation: 


Simplifying
5(x + -4) * x + 5y(y + 2) + 21 = 0

Reorder the terms:
5(-4 + x) * x + 5y(y + 2) + 21 = 0

Reorder the terms for easier multiplication:
5x(-4 + x) + 5y(y + 2) + 21 = 0
(-4 * 5x + x * 5x) + 5y(y + 2) + 21 = 0
(-20x + 5x2) + 5y(y + 2) + 21 = 0

Reorder the terms:
-20x + 5x2 + 5y(2 + y) + 21 = 0
-20x + 5x2 + (2 * 5y + y * 5y) + 21 = 0
-20x + 5x2 + (10y + 5y2) + 21 = 0

Reorder the terms:
21 + -20x + 5x2 + 10y + 5y2 = 0

Solving
21 + -20x + 5x2 + 10y + 5y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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