(2/(X-4)(X-2))=(1/(X-4))+(2/(X-2))

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Solution for (2/(X-4)(X-2))=(1/(X-4))+(2/(X-2)) equation: 


D( X )

X-2 = 0

X-4 = 0

X-2 = 0

X-2 = 0

X-2 = 0 // + 2

X = 2

X-4 = 0

X-4 = 0

X-4 = 0 // + 4

X = 4

X in (-oo:2) U (2:4) U (4:+oo)

(2/(X-4))*(X-2) = 1/(X-4)+2/(X-2) // - 1/(X-4)+2/(X-2)

(2/(X-4))*(X-2)-(1/(X-4))-(2/(X-2)) = 0

(2/(X-4))*(X-2)-(X-4)^-1-2*(X-2)^-1 = 0

(2*(X-2))/(X-4)-1/(X-4)-2/(X-2) = 0

(2*(X-2)^2)/((X-4)*(X-2))+(-1*(X-2))/((X-4)*(X-2))+(-2*(X-4))/((X-4)*(X-2)) = 0

2*(X-2)^2-1*(X-2)-2*(X-4) = 0

2*X^2-9*X-2*X+8+10 = 0

2*X^2-11*X+18 = 0

2*X^2-11*X+18 = 0

2*X^2-11*X+18 = 0

DELTA = (-11)^2-(2*4*18)

DELTA = -23

DELTA < 0

1 = 0

1/((X-4)*(X-2)) = 0

1/((X-4)*(X-2)) = 0 // * (X-4)*(X-2)

1 = 0

X belongs to the empty set

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