3/2(4a-10)=6a-2

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Solution for 3/2(4a-10)=6a-2 equation: 


a in (-oo:+oo)

(3/2)*(4*a-10) = 6*a-2 // - 6*a-2

(3/2)*(4*a-10)-(6*a)+2 = 0

(3/2)*(4*a-10)-6*a+2 = 0

3/2*(4*a-10)-6*a+2 = 0

3/2*(4*a-10)-6*a+2 = 0

2-15 = 0

-13 = 0

-13 = 0

a belongs to the empty set

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