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5(x-4)=3(2x+3)
We move all terms to the left:
5(x-4)-(3(2x+3))=0
We multiply parentheses
5x-(3(2x+3))-20=0
We calculate terms in parentheses: -(3(2x+3)), so:We get rid of parentheses
3(2x+3)
We multiply parentheses
6x+9
Back to the equation:
-(6x+9)
5x-6x-9-20=0
We add all the numbers together, and all the variables
-1x-29=0
We move all terms containing x to the left, all other terms to the right
-x=29
x=29/-1
x=-29
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