2(80-3y)=96+2y

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Solution for 2(80-3y)=96+2y equation: 



2(80-3y)=96+2y

We move all terms to the left:

2(80-3y)-(96+2y)=0

We add all the numbers together, and all the variables

2(-3y+80)-(2y+96)=0

We multiply parentheses

-6y-(2y+96)+160=0

We get rid of parentheses

-6y-2y-96+160=0

We add all the numbers together, and all the variables

-8y+64=0

We move all terms containing y to the left, all other terms to the right

-8y=-64

y=-64/-8

y=+8

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