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9(x+3)=(2x+5)
We move all terms to the left:
9(x+3)-((2x+5))=0
We multiply parentheses
9x-((2x+5))+27=0
We calculate terms in parentheses: -((2x+5)), so:We get rid of parentheses
(2x+5)
We get rid of parentheses
2x+5
Back to the equation:
-(2x+5)
9x-2x-5+27=0
We add all the numbers together, and all the variables
7x+22=0
We move all terms containing x to the left, all other terms to the right
7x=-22
x=-22/7
x=-3+1/7
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